**
**

**
Part III Practice Problems on
Inferential Statistics**

**
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7)
The human services manager is concerned
that employee absenteeism may not be happening equally throughout the week.

Using the 5-step approach to hypothesis testing, investigate her concern at the
.01 level of significance.

**Categorizing
problems
**
**
will help if you do not know what test
to run.**
Absences
Monday
12
Tuesday
8
Wednesday
6
Thursday
9
Friday
15

8) | The marketing director of the We'll Be Famous Company wants to determine
if age has an effect on target market acceptance of Quick Grow Finger Nail
Paste. Using the 5-step approach to hypothesis testing, analyze this data at the .05 level of significance. Categorizing
problems
will help if you do not know what test to run. | ||||||

| |||||||

Would Buy | Won't Buy |
Totals | |||||

Age |
|||||||

Under 20 |
45 | 15 | 60 | ||||

20 and Over | 10 | 30 | 40 |

Part II Instructions: Use two paragraphs consisting of complete sentences to define an hypothesis test related to your major.

**
Part III Instructions:**
Use at least three paragraphs consisting of complete sentences to explain a
business activity of a company you are familiar with, to describe the duties of
a position at this company that would be of interest to you, and to define how
this company could use the 5-step approach to hypothesis testing to solve a
company problem. The wording of this question is specifically designed to give
wide flexibility and freedom when writing your essay.

**
Please
**

**
**1) z of 1.75 from the data is not beyond z critical of 1.96 for the .05 level of significance (divide by 2),
accept the null hypothesis, accounts receivables could equal the $375 stated on
the balance sheet.

2) 1) z of 1.75 from the data is beyond z critical of 1.645 from the .05 level of significance, reject the null hypothesis, average accounts receivables could be larger than the $375 stated on the balance sheet.

3) t of 1.75 from the data is not beyond t critical of 2.064 from the .05 level of significance (divided by 2), accept the null hypothesis, accounts receivables could equal the $375 stated on the balance sheet.

4) t of 1.75 from the data is beyond t critical of 1.711 from the .05 level of significance, reject the null hypothesis, average accounts receivables could be larger than the $375 stated on the balance sheet.

5) t of -2.69 from the data is not beyond t critical of -2.977 from the .01 level of significance (divided by two), accept the null hypothesis, the time it takes to make parts does not differ for the two shifts.

6) t of -5.08 from the data is beyond t critical of -2.132 from the .05 level of significance, reject the null hypothesis, scores improved.

7) 5.0 < 13.28, accept the null hypothesis at the .01 level of significance, absences happen equally throughout the week.

8) 24.24 > 3.84, reject the null hypothesis at the .05 level of significance. There is a relationship and customer acceptance is dependent upon age.

Consider
Quick Statistics Using Microsoft
(TM) Excel

for the fastest and easiest way to do these and other
statistical tests.